Algebra Graph y= (x1)^24 y = (x − 1)2 − 4 y = ( x 1) 2 4 Find the properties of the given parabola Tap for more steps Use the vertex form, y = a ( x − h) 2 k y = a ( x h) 2 k, to determine the values of a a, h h, and k k a = 1 a = 1 h = 1 h = 1 k = − 4 k = 4The graph of y = x 2 is a parabola that opens upwards The vertex of this parabola is at the point where x = 0 y = x 2 If you change x to x 5 so the equation is y = (x 5) 2 then the vertex is at the point where x 5 = 0, that is at x = 5 Thus a change from x to x 5 is a translation of 5 units to the right y = (x 5)2Thus the graph doesn't cross the xaxis at 2
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Graph of y=1/2(x+4)^2-\(y=x^2(x^21)(x^22)^4\) In each case, you should pay particular attention to the points where the curve meets the \(x\) axis To sketch the graph of (i), first notice that we must have \(x(x1)(x2)^4 \geq 0\) in order for \(y\) to take real valuesSubtract y from both sides x^ {2}4x4y=0 x 2 4 x 4 − y = 0 This equation is in standard form ax^ {2}bxc=0 Substitute 1 for a, 4 for b, and 4y for c in the quadratic formula, \frac {b±\sqrt {b^ {2}4ac}} {2a} This equation is in standard form a x 2 b x c = 0 Substitute 1 for a, 4 for b, and 4 − y for c in the quadratic
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Y=(x1)2 4 find p, axis of symmetry, vertices, foci, directrix for this parabola Thankyou! The table for example 1 is obtained by substituting the different xvalues into y = x 2 So for example, when x = 2, then y = (2) 2 = 4 This is graphed by putting a dot on the point (2,4) We then put dots for all the other points in the table (like (4,16), then (3,9) and so onCompute answers using Wolfram's breakthrough technology & knowledgebase, relied on by millions of students & professionals For math, science, nutrition, history
star 48 /5 heart 175 profile Brainly User The vertex of the graph of y = (x 1)2 5 is ( 1,5) 1jaiz4 and 279 more users found this answer helpful heart outlinedPlease Subscribe here, thank you!!! y = a(x − h)2 k where (h,k) is the vertex of the parabola For your equation that means the vertex is (1,4) Plot this point NOTE there is a sign change for the h but not k Now we need another point The easiest to find is by letting x=0 y = 2(0 − 1)2 4 y = 2( − 1)2 4
Use the distributive property to multiply y by x 2 1 Add x to both sides Add x to both sides All equations of the form ax^ {2}bxc=0 can be solved using the quadratic formula \frac {b±\sqrt {b^ {2}4ac}} {2a} The quadratic formula gives two solutions,You can clickanddrag to move the graph around If you just clickandrelease (without moving), then the spot you clicked on will be the new center To reset the zoom to the original click on the Reset button Using "a" Values There is a slider with "a =" on it You can use "a" in your formula and then use the slider to change the value of "aA line has slope 2 and passes through point (2, 4) Find the equation of the line Solution Substitute 2 for m and (2, 4) for (x 1, y 1) in Equation (2) Thus, a line with slope 2 that passes through the point (2, 4) has the equation y = 2x 8 We could also write the equation in equivalent forms y 2x = 8, 2x y = 8, or 2x y 8 = 0
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This problem has been solved!Algebra Graph y=4*2^x y = 4 ⋅ 2x y = 4 ⋅ 2 x Exponential functions have a horizontal asymptote The equation of the horizontal asymptote is y = 0 y = 0 Horizontal Asymptote y = 0 y = 0 the coordinate plane that passes through the 3, 6 and has a slope of four the yintercept of the line is Find the distance between the two points (1,1) ? (2,4) Enter the number that goes beneath the radical symbol
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Algebra > Quadraticrelationsandconicsections> SOLUTION sketch the graph of each ellipse 1x^2/9y^2/4=1 2x^2/9y^2=1 3x^2y^2/4=1 4y^2/4x^2/25=1 5y^2/9X^2/16=1 6x^2/25y^2=1 7x^2y^2/9=1 8x^2y^2/25=1 9x^2/9y^2=1 Log OnQuestion y=(x1)2 4 find p, axis of symmetry, veritces, foci, directix for this parabola Thankyou!EXAMPLE 11 Sketch the graph of y = (x 2)4(x 1)3(x – 1) by finding its intercepts and its limits as x → and x → 0 х SOLUTION The yintercept is f(0) = (2)4( (1) and the xintercepts are found by setting y = 0 X = 2, 1, Notice that since (x 2)4 is positive, the function doesn't change sign at 2;
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Answer by stanbon(757) (Show Source) You can put this solution on YOUR website!Graph (y2)^2=4(x1) Rewrite the equation as Divide each term by and simplify Tap for more steps Divide each term in by Cancel the common factor of Graph the parabola using its properties and the selected points Graph the parabola using its properties and the selected points Direction Opens Left VertexRelated » Graph » Number Line » Examples » Our online expert tutors can answer this problem Get stepbystep solutions from expert tutors as fast as 1530 minutes
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The graph of the function y = f (x) is vertically stretched about the xaxis by a factor of 2 y x 2 4 6246 2 424 0 y = f (x) a) Determine the domain and range of the transformed function b) Explain the effect that a vertical stretch has on the domain and range of a functionAll equations of the form a x 2 b x c = 0 can be solved using the quadratic formula 2 a − b ± b 2 − 4 a c The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction x^ {2}4xy5=0 x 2 4 x − y − 5 = 0 This equation is in standard form ax^ {2}bxc=0 Substitute 1 for a, 4 for b, andConsider the given point and the new graph (− 3, 5) and y = g(x 1) − 3 Now, let us take x 1 = − 3 x = − 4 Now, let us take y = g(− 3) − 3 = 5 − 3 = 2 Hence, the corresponding location of the given point on the graph of y = g(x 1) − 3 is (− 4, 2)
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Answer to Graph the function f(x) = (x 1)^2 4 by starting with the graph of y = x^2 and using transformations By signing up, you'll getSwap sides so that all variable terms are on the left hand side x^ {2}2x=y4 Subtract 4 from both sides x^ {2}2x1^ {2}=y41^ {2} Divide 2, the coefficient of the x term, by 2 to get 1 Then add the square of 1 to both sides of the equation This step makes the left hand side of 58 jyoung So if you look at the equation you can see the yintercept slope yintercept ↓ ↓ y = x 2 The yintercept is where the line crosses the yaxis So which ever graph has 2 as the yintercept in correctIts more complex when the graphs have the same intercept but in this case this should be easy to find So looking at
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The graph of (x2)/4=1/(y4) is a visual presentation of the function in the plane On the given graph you can find all of the important points for function (x2)/4=1/(y4) (if they exist) You can always share this solutionThe area of the figure bounded by the parabola (y − 2) 2 = x − 1, the tangents to it at the point with the ordinate 3 and the Xaxis is View solution Determine the length of the curve x = 2 1 ( e y − e − y )Question 2 The Graph Of (x 1)2 (y2)2 = 4 Is Shown On The Right Use Implicit Differentiation To Find The Slopes Of The Tangent Lines At The Points On The Graph Where X = 22 Check Your Answers By Visually Estimating The Slopes On The Graph In The Figure
The Graph Of A Quadratic Function Is Shown Below Which Statements About This Graph Are True Select All That Apply The Graph Has A Y Intercept At 0 8 The Graph Has A Maximum
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Graph x=1y^2 Reorder and Find the properties of the given parabola Tap for more steps Rewrite the equation in vertex form Tap for more steps Complete the square for Tap for more steps Use the form , to find the values of , , and Consider the vertex form of a parabolaIn fact (2)^x is real if and only if x can be written as p/q where p and q are integers with no common factors other than 1 and q is odd If x=p/q is such a rational number then (2)^x=2^x if p is even and (2)^x=(2^x) if p is odd To see the graph of y=(2)^x first consider the graphs of y=2^x and y=(2Compute answers using Wolfram's breakthrough technology & knowledgebase, relied on by millions of students & professionals For math, science, nutrition, history
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Steps to graph x^2 y^2 = 4 Explanation This is the equation of a circle with its centre at the origin Think of the axis as the sides of a triangle with the Hypotenuse being the line from the centre to the point on the circle By using Pythagoras you would end up with the equation given where the 4 is in fact r2 To obtain the plot points manipulate the equation as below Given x2 y2 = r2 → x2 y2 = 4 y = x 2 4 Compare it to standard form of parabola y = a x 2 bx c a = 1 , b = 0, c = 4 We know that parabola like a curve a is positive , so the parabola opens upward The parabola giving us all real numbers is the domain To find the range axis of symmetry x = b /2a x = 0 Substitute the x value in y = x 2 4 y = 0 4
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See the answer Sketch the graph of each function Find the Axis of Symmetry and Vertex 2 y= 4x 2 8x 2 3 y = 2x 2 16x 29 4 y = 2x 2 4 x 1 5 y = 2x 2 8x 6 6 y = x 2 4x 8Get stepbystep solutions from expert tutors as fast as 1530 minutes where m denotes the slope of the line and c denotes the yintercept we get ie the slope of line is 4 Also we know that the slope of parallel line is equal so we will check in each of the following options whose slope is 4 1) This equation could also be represented as Hence its slope is which is not equal to 4 Hence option 1 is incorrect 2)
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Answer to The graph of (y − 1)2 = 4(x 1) is which of the following? The figure shows the graph of the function y=(x1)^24 Identify the xvalues for which the function in increasing {xx>1} 4 Identify the x and yintercepts of the graph Xintercepts (1,0) and (3,0) yintercepts (0,3) 5 a batter hits a baseball into the air at an angle The height of the ball in feet, is modeled by a quadratic functionAnswer to Consider the following y=9x^2ln (x), (1,9) Find an equation of the tangent line to the graph of the function at the point By signing
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Y > 3x 4 y < 1/2x 1 1 The graph of y > 3x − 4 has shading above a dashed line 2 The graph of y < 1/2x 1 has shading below a dashed line 3 The graphs of the inequalities will intersect 4 There are no solutions to the system 5 The graphs of the two inequalities intersect the yTangent of y=x^2, at (2,4) \square!Sin (x)cos (y)=05 2x−3y=1 cos (x^2)=y (x−3) (x3)=y^2 y=x^2 If you don't include an equals sign, it will assume you mean " =0 " It has not been well tested, so have fun with it, but don't trust it If it gives you problems, let me know Note it may take a few seconds to finish, because it has to do lots of calculations
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Question 3094 graph y 2 = 1/4(x 2) I know this is the pointslope equation, so I know the slope is 1/4, but uncertain how to determine what points to plot on a graph Please help me create the graph Found 2 solutions by Alan3354, stanbonGraph the parabola, y =x^21 by finding the turning point and using a table to find values for x and yVideo Lectures on DVD with Optional Subtitles for College Algebra (4th Edition) Edit edition Problem 22T from Chapter 7
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//googl/JQ8NysSketching the Graph of the Circle (x 2)^2 (y 3)^2 = 4In this math video lesson I show how to graph y=(1/4)x2 The equation in this video is in slopeintercept form, y=mxb, and is a common way to graph an equGraph a function by translating the parent function
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